10000x^2+4002x+0.8=0

Solution for 10000x^2+4002x+0.8=0 equation:

10000x^2+4002x+0.8=0

a = 10000; b = 4002; c = +0.8;
Δ = b2-4ac
Δ = 40022-4·10000·0.8
Δ = 15984004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15984004}=3998$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4002)-3998}{2*10000}=\frac{-8000}{20000}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4002)+3998}{2*10000}=\frac{-4}{20000}
=-1/5000
$